VS2013에서이 기능을 사용하려고 시도합니다 (Variadic macro trick 및 C++ preprocessor __VA_ARGS__ number of arguments 참조).C++ : Visual Studio에서 각 가변 인수를 처리하십시오.
afaik 중복 버전이 아닙니다 (다른 버전은 GCC에서만 작동합니다).
어떤 아이디어가 잘못 되었나요? 나는 ... 거의 다 해요
#define _EXPAND(x) x
#define _VA_NARGS_IMPL(_1_, _2_, _3_, _4_, _5_, N, ...) N
#define _VA_NARGS_IMPL2(...) _EXPAND(_VA_NARGS_IMPL(__VA_ARGS__, 4, 3, 2, 1, 0))
#define _PUSH_X_FRONT(...) X, __VA_ARGS__
/*
Returns the number of arguments specified.
#ifndef _MSC_VER
#define VA_NARGS(...) _VA_NARGS_IMPL2(X,##__VA_ARGS__)
*/
#define VA_NARGS(...) _VA_NARGS_IMPL2(_PUSH_X_FRONT(__VA_ARGS__))
// testing is gewd
static_assert(VA_NARGS() == 0, "VA_NARGS() failed for 0 arguments");
static_assert(VA_NARGS(one, two, three, four) == 4, "VA_NARGS() failed for 4 arguments");
#define _VARARG_IMPL2(N, Macro, ...) Macro##N(__VA_ARGS__)
#define _VARARG_IMPL(N, Macro, ...) _VARARG_IMPL2(N, Macro, __VA_ARGS__)
// Helper function for variadic macros with per-argument processing.
#define VARARG(Macro, ...) _VARARG_IMPL(VA_NARGS(__VA_ARGS__), Macro, __VA_ARGS__)
#define _Quote1(x) #x
#define _Quote2(x, ...) #x, _Quote1(__VA_ARGS__)
#define _Quote3(x, ...) #x, _Quote2(__VA_ARGS__)
#define _Quote4(x, ...) #x, _Quote3(__VA_ARGS__)
// Treat each argument as a string literal, encompassing in quotes.
#define Quote(...) VARARG(_Quote, __VA_ARGS__)
질문 :
constexpr char *a[] = { Quote(a, b) };
// WHY does the above produce {"a, b"} with msvc?
// The following produces {"a", "b"} as expected
constexpr char *a[] = { _Quote2(s, c) };