Mysql Sum Column

Question

저는 mysql에 처음이므로 제 작업에 대한 지불 일정을 잡으려고합니다. 총계를 "지불금"으로 표시해야합니다.

<?php 

     $sql = "SELECT id, DATE_FORMAT(datum, '%d/%m/%Y'), tijd, uren, floor(uren*loon) as payment FROM uren_gewerkt"; 

     $result = $conn->query($sql); 

     if ($result->num_rows > 0) { 
      echo "<table><tr><th>Datum</th><th>Tijden</th><th>Uren</th><th>Loon</th></tr>"; 
      // output data of each row 
      while($row = $result->fetch_assoc()) { 
       echo "<tr><td>".$row["DATE_FORMAT(datum, '%d/%m/%Y')"]."</td><td>".$row["tijd"]."</td><td>".$row["uren"]."</td><td>&euro;".$row["payment"]."</td></tr>"; 
      } 
      echo "</table>"; 

      echo "Totaal:"; //Sum of payment goes here 

     } 
     else { 
      echo "0 results"; 
     } 
    ?> 

참고 "룬은"(바닥에서 (uren의 *의 아비)은 고정 된 수의 (9.56)

Answer 1

SELECT SUM(floor(uren*loon)) as total FROM uren_gewerkt 

또는 PHP에서 할 :

$total = 0; 
//here goes your while loop 
while($row = $result->fetch_assoc()) { 
    echo "<tr><td>".$row["DATE_FORMAT(datum, '%d/%m/%Y')"]."</td><td>".$row["tijd"]."</td><td>".$row["uren"]."</td><td>&euro;".$row["payment"]."</td></tr>"; 
    $total += $row["payment"]; 
} 
echo "Totaal: &euro;".$total;